A 0.060-kg tennis ball, moving with a speed of 5.42 m/s , has a head-on collisio

Question

A 0.060-kg tennis ball, moving with a speed of 5.42 m/s , has a head-on collision with a 0.085-kg ball initially moving in the same direction at a speed of 3.12 m/s . Assume that the collision is perfectly elastic.

a) Determine the speed of the 0.060-kg ball after the collision.

b)Determine the direction of the velocity of the 0.060-kg ball after the collision. 1.in the direction of the initial velocity 2.in the direction opposite to the initial velocity

C)Determine the speed of the 0.085-kg ball after the collision.

D)Determine the direction of the velocity of the 0.085-kg ball after the collision. 1.n the direction of the initial velocity 2.in the direction opposite to the initial velocity

Explanation / Answer

a)

m1 = first ball = 0.06 kg

Vo1 = initial velocity of ball 1 = 5.42 m/s

m2 = second ball = 0.085 kg

Vo2 = initial velocity of ball 2 = 3.12 m/s

Vf1 = final velocity of ball 1

Vf2 = final velocity of ball 2

using conservation of momentum

m1 V1o + m2 V2o = m1 V1f + m2 V2f

(0.06) (5.42) + (0.085) (3.12) = (0.06) V1f + (0.085) V2f

(0.06) V1f + (0.085) V2f = 0.59                        eq-1

For perfectly elastic collisions

V2f - V1f = V1o - V2o

V2f - V1f = 5.42 - 3.12

V2f = V1f + 2.3                              eq-2

using eq-1 and eq-2

(0.06) V1f + (0.085) (V1f + 2.3 ) = 0.59   

V1f = 2.72 m/s

b)

direction : same direction as before the collision

c)

V2f = V1f + 2.3 = 2.72 + 2.3 = 5.02 m/s

d)

1.n the direction of the initial velocity

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