A 0.0600-kg ice cube at 30.0°C is placed in 0.400 kg of 35.0°C water in a very w

Question

A 0.0600-kg ice cube at 30.0°C is placed in 0.400 kg of 35.0°C water in a very well-insulated container. What is the final temperature in degrees Celsius?

_____°C

Question 2

An aluminum calorimeter with a mass of 100 g contains 229.0 g of water. The calorimeter and water are in thermal equilibrium at 20.0°C. An iron block with an initial temperature of 115°C is placed into the water. The entire system stabilizes at a final temperature of 28.9°C. Determine the mass of the iron block in grams. Assume that no heat is transferred to or from the surroundings.

____g

Question 3

(a) Calculate the rate of heat conduction (in W) through house walls that are 13.5 cm thick and that have an average thermal conductivity twice that of glass wool. Assume there are no windows or doors. The surface area of the walls is 105 m2 and their inside surface is at 23.0°C, while their outside surface is at 5.00°C.

___W

(b) How many 1 kW room heaters would be needed to balance the heat transfer due to conduction? (Round your answer to the next whole integer.)

___kW room heaters

PLEASE ANSWER ALL THE QUESTIONS AND DONT GIVE ANY WRONG ANSWERS THANKS FOR YOUR HELP !

Explanation / Answer

1)
Using principle of caloriemetry

Heat gained by ice = Heat lost by water

HEat gained by ice from -30 deg C to 0 deg C + heat gained by ice at 0 deg C to become water at 0 deg C + heat gained by water at 0 deg C to become water at T deg C = heat lost by water at 35 deg C to become water at T deg C

[m_ice*S_ice*(dT)] + (m_ice*Lf) + (m_ice*S_water*dT) = m_water*S_water*dT

given that m_ice = 0.06 Kg

S_ice is the specific heat capacity of ice = 2090 J/kg-C

S_water is the specific heat capacity of water = 3190 J/Kg-C

Lf is the latent heat of fusion = 3.33*10^5 J/Kg

and also m_water = 0.4 kg

then

(0.06*2090*30)+(0.06*3.33*10^5)+(0.06*3190*T) = (0.4*3190*(35-T))

T = 14.25 deg C

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