A 0.02000 L sample of 0.00483 M Zn2+ is titrated with 0.04061 L of 0.00683 M EDT
ID: 916987 • Letter: A
Question
A 0.02000 L sample of 0.00483 M Zn2+ is titrated with 0.04061 L of 0.00683 M EDTA in a solution buffered to pH = 9.0. Calculate the concentration of Zn2+ in solution as the pZn2+. ** please show work ** A 0.02000 L sample of 0.00483 M Zn2+ is titrated with 0.04061 L of 0.00683 M EDTA in a solution buffered to pH = 9.0. Calculate the concentration of Zn2+ in solution as the pZn2+. ** please show work ** A 0.02000 L sample of 0.00483 M Zn2+ is titrated with 0.04061 L of 0.00683 M EDTA in a solution buffered to pH = 9.0. Calculate the concentration of Zn2+ in solution as the pZn2+. ** please show work **Explanation / Answer
A 0.02000 L sample of 0.00483 M Zn2+ is titrated with 0.04061 L of 0.00683 M EDT
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