Vertically polar Wed light with an intensity of 0.65 W/m^2 passes through a pola

Question

Vertically polar Wed light with an intensity of 0.65 W/m^2 passes through a polarizer whose transmit sion axis is an angle of 29.0degree with the vertical what is intensity of the transmitted light? a. 0.316 W/m^2 b. 0.165 W/m^2 c. 0.497 W/m^2 d. 1.647 W/m^2 A concave mirror produces a virtual image that is nine time as tall as the object If the object is 26 cm in front of the mirror, what is the image distance? a) -234 cm b) -124cm c) -214 cm d) -114 cm Light enters a container of hquM at an angle of 49' to the normal; the refracted beam makes an angle of 29' with the normal. Calculate the index of refraction of this liquid. a) 1.34 b) 1.56 c) 2.11 d) 1-44 17. Two lenses that are I = 54 cm are used to form an image, as shown In figure. Lens 1 Is converging and has 4 focal length f_1 = 16 cm; lens 2 is diverging and has a focal lengthf_2, = -7.0 cm. Determine the distance from lens 1 to the final image. a) 30.6 cm b) 12.8 cm c) 50.8 cm d) 23.6 cm Your friend is 2.0 m tall. When she stands 3.7 m from you, what is the height of her image formed on the retina of your eye? Consider the eye to consist of a thin lens 1.7 cm from the retina a) 0.92 cm b) 0.72 cm c) 1.12 cm d) 1.02 cm A magnifying glass is a single convex lens with a focal length of f = +15.0 cm. What is the angular magnification when this lens forms a image at -infinity? a) 1.13cm b) 1.67 cm c) 1.44 cm d) 0 99 cm

Explanation / Answer

14) I = 0.65 x cos229 = 0.497 W/m2

15) v/u = -(hi/ho) = -9

v = -9 x 26 = -234 cm

16) using lens formula 1/f = 1/v - 1/u

1/16 = 1/v1 - 1/(-24) => v1 = 48 cm

u2 = -(54-48) = -6 cm

1/(-7) = 1/v - 1/(-6) => v = -42/13

so required distance = 54 - 42/13 = 50.8 cm

17) v/u = hi/ho   => hi = 1.7 x 2/370 = 0.009189 m = 0.9189 cm = 0.92 m

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