What is the magnitude and direction of the magnetic force on the Wire due to the

Question

What is the magnitude and direction of the magnetic force on the Wire due to the Wire I above? Assume parallel wires 30 m long and 2.0 cm apart, causing the same direction currents. I_i = 100 A and I_2 = 30 A. as shown in figure below. (Ignore gravity The magnetic field (in milliTesla) through a loop with area 0.10 m; and 10 turns is made to vary according to the relation: B(t) = 4.Ot^2 - 2.0. where t is in seconds. Assuming the magnetic field is perpendicular to the surface of the loop. What is the magnitude of voltage induced in the loop at t = 1.0s? 23 mV 18mV 12mV 8.0 mV 2.0 mV A resistance of 42 Ohm. a capacitor of capacitive reactance 25 Ohm and inductor of inductive reactance 25 Ohm are connected in series to a 170-V (peak voltage). 60 Hz power source What is the peak current in this circuit? 1.0 A 2.0 4.0 A 8.0 A 10 A

Explanation / Answer

4. from lenz law , option C:

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5. magnetic force between parallel wires is given by F = uo i1i2L/2pi d

F = 4*3.1*10^-7 * 100*30* 30/(2 *3.14 * 0.02)

F = 0.9 N upWard

option B

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6.

B = 4t^2 -2

dB/dt = 8t

at time t = 1s, B = 8* 1 = Tesla

induced emf e = NA dB/dt

emf e = 10 * 0.1 * 8/1

emf e = 8 V olts

option D

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Impedence Z^2 = R^2 + (XL-Xc)^2

Z^2 = (42^2 + (25 -25)^2

Z = 42 ohms

peak Curent I = V/Z = 170/42 = 4.04 Amps

option C

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