The magnetic flux through each turn of a 130-turn coil is given by = 8.50 times
ID: 1450500 • Letter: T
Question
The magnetic flux through each turn of a 130-turn coil is given by = 8.50 times 10^-3 sin(omega t), where co is the angular speed of the coil and is in webers. At one instant, the coil is observed to be rotating at a rate of 9.20 times 10^2 rev/min. (Assume that t is in seconds.) What is the induced emf in the coil as a function of time for this angular speed? (Use the following as necessary: t. Do not use other variables, substitute numeric values. Assume that epsilon is in volts. Do not include units in your answer.) epsilon = What is the maximum induced emf in the coil for this angular speed? VExplanation / Answer
a)
N = 130 turns
flux through each turn = 8.5*10^-3*sin(w*t)
w = 920 rev/min
= 920*2*pi/60
= 96.3 rad/s
induced emf = the rate of change of magnetic flux
= d(130*8.5*10^-3*sin(w*t))/dt
= 130*8.5*10^-3*cos(w*t)*w
= 130*8.5*10^-3*cos(96.34*t)*96.34
= 106.5*cos(96.34*t)
b) maximum induced emf = 106.5 volts
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