Your friend, Wilma, has built a \"mobile\" to hang over her infant daughter\'s c

Question

Your friend, Wilma, has built a "mobile" to hang over her infant daughter's crib she has built it as instructed-she thinks, but it won't hang properly. Check out the diagram on the mobile. It is 60.0 cm long and is suppose to be able to hang with connector located at the mid-point position the 30.0-cm mark. All the bears are equally spaced apart. Here's some info that you'll need in order to help Wilma: The mass of the two larger bears is m_L = 0.310 kg. The mass of the two smaller bears is m_s = 0.200 kg. The suspending bar is made of Etherium, which is infinitely strong and has no mass. What is the horizontal location (X_cm) of the center of mass?

Explanation / Answer

Let horizontal location of com be at X
X = [ms*0 + ml*20 + ms*40 + ml*60]/[2*[ms + ml]]
X = [0.31*20 + 0.2*40 + 0.31*60]/2*[0.2+0.31] = 32.1568 cm

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