Your friend, Wilma, has built a \"mobile\" to hang over her infant daughter\'s c

Question

Your friend, Wilma, has built a "mobile" to hang over her infant daughter's crib. She has built it as instructed -she thinks, but it won't hang properly. (She purchased it from lkea.) Check out the diagram of the mobile zero Rn n s 60.0 cm long and is supposed to be able to hang with the connector located at the mid-point position -the 30.0-cm mark. All the bears are equally spaced apart. Here's some info that you'll need in order to help Wilma: The mass of the two larger bears is mL = 0.310 kg. * The mass of the two smaller bears is ms 0.210 kg. The suspending bar is made of Etherium, which is infinitely strong and has no mass. Answer the two questions below, using three significant digits Part A: What is the horizontal location (om) of the center of mass? (Specify your answer in centimeters.)

Explanation / Answer

there are 4 masses.
m1 = 0.210 Kg
x1 = 0 m
m2 = 0.310 Kg
x2 = 20 m
m3 = 0.210 Kg
x3 = 40 m
m4 = 0.310 Kg
x4 = 60 m

Xcm = (m1*x1+m2*x2+m3*x3+m4*x4)/(m1+m2+m3+m4)
= (0.210*0 + 0.310*20 + 0.210*40 + 0.310*60)/(0.210+0.310+0.210+0.310)
= 33.2/(1.04)
= 31.9 m

centre of mass will be at 31.9 m

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