The density of your unknown polymer was tested using H2O. If the density of your

Question

The density of your unknown polymer was tested using H2O. If the density of your unknown was tested using ethanol instead of water, what would be the result? The density of your unknown polymer was tested using H2O. If the density of your unknown was tested using ethanol instead of water, what would be the result? The density of your unknown polymer was tested using H2O. If the density of your unknown was tested using ethanol instead of water, what would be the result? The density of your unknown polymer was tested using H2O. If the density of your unknown was tested using ethanol instead of water, what would be the result? The density of your unknown polymer was tested using H2O. If the density of your unknown was tested using ethanol instead of water, what would be the result? The density of your unknown polymer was tested using H2O. If the density of your unknown was tested using ethanol instead of water, what would be the result? The density of your unknown polymer was tested using H2O. If the density of your unknown was tested using ethanol instead of water, what would be the result?

Explanation / Answer

Density of unknown polymer was tested using H2O (density= 1 g/mL)
If the density of your unknown was tested using ethanol (density= 0.789g/mL) (abbreviated EtOH) instead of water, the result of the density of the polymer would be:
(1 / 0.789) = 1.267 times more

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