A particle of charge +23 uC and mass 1.3x10^ -16 kg moves at a speed of 2000 m/s

Question

A particle of charge +23 uC and mass 1.3x10^ -16 kg moves at a speed of 2000 m/s and is velocity vector lies in the x-y plane. There is a magnetic field of magnitude 0.88 T along the +z direction. The magnetic force on the particle causes the particle to move in a circle that lies in the x-y plane. (a) Find the radius of this circle (b) Find the period of the motion (c) if the particle is moving in the -x direction at t=0, is the circular motion clockwise or is it counterclockwise as views from the x-y plane, i.e., looking down from the +z axis? Include a diagram of the situation.

Explanation / Answer

a) radius of the circle is r = (m*v)/(q*B)

m is the mass of the particle

v is the speed of the particle

q is the charge of the particle

B is the magnetic field

r = (1.3*10^-16*2000)/(23*10^-6*0.88) = 1.28*10^-8 T

b) period T = 2*pi*r/v = (2*3.142*1.28*10^-8)/(2000) = 4.02*10^-11 sec

c) counterclockwise direction

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