A particle of charge +3.0 x 10-8 is in a unifrom electric field directed to the

Question

A particle of charge +3.0 x 10-8 is in a unifrom electric field directed to the left. It is released from rest and moves a distance of 5.0 cm and its kinetic energy is increased by +4.5 x -4 J.

a) What is the work fone by the electric force?______________ units?_____________

b) What is the magnitude of the electric field? _______________units?____________

c)What is the electric potential of the starting point relative to the endpoint of the path____________? units?________________

Use symbols for the units.

Explanation / Answer

a) Work done = -change in PE= change in KE = 4.5 x 10^-4 J b) delta V=delta PE/q delta V= -Ed -Ed = delta PE/q E=-delta PE/qd = 300000 N/C c) V1=Ed = (300000)(.05) = 15000 V V2 = Ed = (300000)(0) = 0 V Starting point is 15000 V more than at end of path

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