A 410-loop circular armature coil with a diameter of 8.0 cm rotates at 180 rev/s

Question

A 410-loop circular armature coil with a diameter of 8.0 cm rotates at 180 rev/s in a uniform magnetic field of strength 0.60 T. What is the rms voltage output of the generator What would you do to the rotation frequency in order to double the rms voltage output To double the output voltage, you must increase by four times the rotation frequency. To double the output voltage, you must decrease by two times the rotation frequency. To double the output voltage, you must treble the rotation frequency. To double the output voltage, you must double the rotation frequency.

Explanation / Answer

the equation for maximum voltage is

V_max = NBA w= 410(0.6)(pi ( 8*10^-2/2)^2)180 rev/s( 2 pi rad/ rev) = 1397.0658816 V

RMS voltage is

V_rms = V_max/sqrt 2 = 988 V

--------------------------------------------------

(2)

   V_rms    V_max    

Hence to double V_rms must also be doubled.

'   =   2

         =   2* 180

         =   360   rev/s

to double the output voltage you must double the rotation frequency

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