A circular solenoid of radius R = 2cm passes through a square loop of wire with

Question

A circular solenoid of radius R = 2cm passes through a square loop of wire with 1 turn and sides of length L = 150. The solenoid is wound with N = 150 turns of over a length 20cm. The solenoid is connected to a resistor and therefore the current in the solenoid is de creasing according to the function Isol = I0e^-t/T where I0 = 0.1A and t = 40s. The system is drawn to the right. The magnetic field in the solenoid points out of the page as drawn. Select the direction of the induced current in the conducting square loop (dark square) shown on the diagram. Select One of the Following: (a) clockwise (b) counterclockwise (c) There is no induced current.

Explanation / Answer

here,

correct optin is: counter clockwise,

because,

magnetic field in a solinoid is out of the page and strength of the magnetic field is decreases,

according Lenz's law,

this decrease in magnetic field will induce current and this current always opposes the change in magnetic field

hence, magnetic field due to induced current will try to increases the magnetic field which is out of the page,

by using right hand rule,

if the magnetic field is out of the page,

then, direction of induced current must be counter clockwise,

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