A circular loop with radius 0.2 m is placed in uniformmagnetic field of magnitud
ID: 1748394 • Letter: A
Question
A circular loop with radius 0.2 m is placed in uniformmagnetic field of magnitude 0.850 T. The normal to the loopmakes an angle of 30 degrees with respect to the direction of B. Ifthe field increases to 0.95 T, what is the increase in magneticflux thru the loop? Credit given for answers with the above values included in theanswer. Thanks NOT A TEXT PROBLEM A circular loop with radius 0.2 m is placed in uniformmagnetic field of magnitude 0.850 T. The normal to the loopmakes an angle of 30 degrees with respect to the direction of B. Ifthe field increases to 0.95 T, what is the increase in magneticflux thru the loop? Credit given for answers with the above values included in theanswer. Thanks NOT A TEXT PROBLEMExplanation / Answer
Increase in magnetic flux = d ( B. A ) = d ( BA cos ) = A cos * dB where A = area of the loop = R ^ 2 = * ( 0.2 m ) ^ 2 = 0.12566 m ^ 2 = 30degrees dB = change inmagnetic filed = 0.95 T So, increase in mag flux = 0.018414 weberRelated Questions
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