6. If you calibrate vour microscope so that 10 reticule units seen through the e

Question

6. If you calibrate vour microscope so that 10 reticule units seen through the eyepiece corresponds to 0.06 mm on the slide, then you would be able to measure the size of cells and other structures by just using the ocular lens reticule units. For example, if a cell on the slide was 10 reticule units long, it would be 0.6 mm long. If the cell was 20 reticule units in diameter - how could we figureut is size? We could set up a ratio and a proportion. For example: 10 reticule units 20 reticule units , then 10x 20x0.06mm 0.06 mm So: 10x- 12 and x 1.2 0.12 mm 10 Try this with the following: 10 reticule units 0.5 reticule units 0.06 mm A: 10reticule units -2s ieticule units 0.06 mm B: Which of the two above is most likely a eukaryotic cell? How did you decide this? How do we know that I reticule unit is equivalent to 0.006 mm? Show the ratio.

Explanation / Answer

A. 10 reticule units/0.06 mm = 0.5 reticule units/x

By cross-multiplying, 10x = 0.06 x 0.5 => x = 0.003 mm = 3 microns

B. 10 reticule units/0.06 mm = 2.5 reticule units/x

=> 10x = 0.06 x 2.5 => x = 0.015 mm = 15 microns

The cell in 'B' may be an eukaryotic cell, since eukaryotic cells range from 10-100 microns (1mm = 103 microns), unline prokaryotic cells, which range from 0.1 to 5 microns

If we solve the following ratio:

10 reticule units/0.06 mm = 1 reticule units/x => 10x = 0.06 x 1 => x = 0.06/10 = 0.006. Thus, 1 reticule unit = 0.006mm

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