similarly to a plate of a capacitor. You and your friend like to play the follow

Question

similarly to a plate of a capacitor. You and your friend like to play the following game (instead of doing the lab work that's required), Your friend sets up a uniform electric field and you need to figure out the corresponding electric field function. You take a voltmeter and fine that there is a 5 V difference from the origin to the point (1, 0) an. You then measure a voltage difference of 8 V from the origin to the point (0, 2) an. If you placed a 10 gram particle whose charge was = 10 mu C in this field, starting it from rest at the origin, what would its speed be when it reaches the point (5, 4) cm?

Explanation / Answer

from the given data, Ex = delta_Vx/x

= 5/0.1

= 500 N/c

ax = q*Ex/m

= 10*10^-6*500/(10*10^-3)

= 0.5 m/s^2

Aplly, vx^2 - vox^2 = 2*ax*x

vx = sqrt(2*ax*x)

= sqrt(2*0.5*0.5)

= 0.707 m/s

Ey = delta_Vy/y

= 8/0.02

= 400 volts

ay = q*Ey/m

= 10*10^-6*400/(10*10^-3)

= 0.4 m/s^2

Aplly, vy^2 - voy^2 = 2*ay*y

vy = sqrt(2*ay*y)

= sqrt(2*0.4*0.4)

= 0.566 m/s

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.