The following data gives stopping potential V 0 versus wavelength for photoelect

Question

The following data gives stopping potential V0 versus wavelength for photoelectrons produced from a metal surface. (Be sure to include the correct units and use three significant figures.)

Table 1

1.07

Use an analysis similar to that used in the inlab procedure to determine the work function (in eV) for this surface. (Use

1 eV = 1.602 1019 J,

e = 1.602 1019 C,

c = 2.998 108 m/s,

and

h = 6.626 1034 J · s = 4.136 1015 eV · s

as necessary.)

(nm) V0
(volts) 50 22.1 100 9.31 150 5.17 200 3.05 250 1.92 300

1.07

Explanation / Answer

E = Wo + KE

work function = Wo = E - KE = E + Vo*e = hc/L + (vo*e) J

Wo = (h*c/eL)+Vo   eV

(1)

L = 50 nm

Wo = (6.626*10^-34*3*10^8/(1.602*10^-19*50*10^-9))+(22.1)

Wo = 46.92 eV

(2)

L = 100 nm

Wo = (6.626*10^-34*3*10^8/(1.602*10^-19*100*10^-9))+(9.31)

Wo = 21.72 eV

3)

L = 150 nm

Wo = (6.626*10^-34*3*10^8/(1.602*10^-19*150*10^-9))+(5.17)

Wo = 13.44 eV

4)

L = 200 nm

Wo = (6.626*10^-34*3*10^8/(1.602*10^-19*200*10^-9))+(3.05)

Wo = 9.254 eV

5)

L = 1.92

Wo = (6.626*10^-34*3*10^8/(1.602*10^-19*250*10^-9))+(1.92)

Wo = 6.88 eV

6)

L = 1.07

Wo = (6.626*10^-34*3*10^8/(1.602*10^-19*300*10^-9))+(1.07)

Wo = 5.21 eV

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