The following data gives stopping potential Vnot versus wavelength for photo ele
ID: 1731933 • Letter: T
Question
The following data gives stopping potential Vnot versus wavelength for photo electrons produced from a metal surface. Use an an analysis similar to that used in the i lab procedure to determine the work function (in eV) for this surface.-Pearson, Myuab & Masters x y?202 ut. Protoetere tn t?dep 18914185 Thefo owing a gives stopping potential Vs wus-avelength for photoelectrons pod ced trom· significant figures.) tal sutace. (Be sre to de the erred unt and Table 1 (nm) (volts) use an analysis smar to that used the inlab procesare to determine tse work Met on ???? tha snace. (use iee _r.coa rio-sa --,sa ,so -2.vse " 10' m/s, and h-6.626 × 10-34 , . .. 4.136 . 10. 15.v.sasnoce.wy.) EPIC
Explanation / Answer
Photo electric equation
E = W+k.e
W = hc/lambda0 work function
k max = eV0 , V0 is stopping potential
E = hc/lambda0+ e*V0
so work function W is
W = E - k.e max
W = (h*c/lambda)- eV0
W = ((6.626*10^-34*2.998*10^8)/(50*10^-9))- (1.602*10^-19*22)
W = 4.485496*10^-19 J
for lambda = 100 nm, V0 = 9.28 V
W = (h*c/lambda)- eV0
W = ((6.626*10^-34*2.998*10^8)/(100*10^-9))- (1.602*10^-19*9.28)
W = 4.998188*10^-19 J
for lambda = 150 nm, V0 = 5.17 V
W = (h*c/lambda)- eV0
W = ((6.626*10^-34*2.998*10^8)/(150*10^-9))- (1.602*10^-19*5.17)
W = 4.9608253*10^-19 J
for lambda = 200 nm, V0 = 3.13 V
W = (h*c/lambda)- eV0
W = ((6.626*10^-34*2.998*10^8)/(200*10^-9))- (1.602*10^-19*3.13)
W = 4.918114*10^-19 J
for lambda =250 nm, V0 = 1.92 V
W = (h*c/lambda)- eV0
W = ((6.626*10^-34*2.998*10^8)/(250*10^-9))- (1.602*10^-19*1.92)
W = 4.8700592*10^-19 J
for lambda =300 nm, V0 = 1.05 V
W = (h*c/lambda)- eV0
W = ((6.626*10^-34*2.998*10^8)/(300*10^-9))- (1.602*10^-19*1.05)
W = 4.93948267*10^-19 J
the average of the above values is W = 4.86203 *10^-19 J
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