I need help on this problem. Thank you for help!!! A circuit diagram is shown be

Question

I need help on this problem. Thank you for help!!!

A circuit diagram is shown below that can be analyzed using equivalent resistance principles. The rules for series and parallel resistors are: Series Resistors Resistance adds Voltage adds Current is the same Parallel Resistors Resistance inverse adds Voltage is the same Current adds Use the rules for series and parallel resistors to find the equivalent resistance of the circuit. Express your answer using two significant figures. For the circuit shown in the figure (Figure 1) find the current through each resistor. Express your answers using two significant figures. Enter your answers numerically separated by commas. For the circuit shown in the figure find the potential difference across each resistor. Express your answers using two significant figures. Enter your answers numerically separated by commas.

Explanation / Answer

(a)The resistance 6 and 4 are in series therefore their equivalent becomes 10
which is in parallel with 15 ohm
therefore the equivalent will be
= 15*10 / (15+10) = 6
which is in series with the 6 ohm
therfore the equivalent resistance of the circuit is = 6+6 = 12 ohm
(b) Current in the circuit = 24/12 = 2 Ampere (I = V/R)
Therefore current in the 6 ohm resistance is 2 A
Now the current get divided into two branch therefore
Consider them as I1 and I2 in the 15 ohm and other branch respectively.
therfore by KCL
I = I1+I2 -------------------(1)
We know that since both branch are in parallel therefore the potential will be same
15I1 = 10 I2
1.5I1 = I2
from equation 1
2 = I1+ 1.5I1
I1 = 0.8 A
I2 = 1.2 A
therefore the current in 15 ohm resistance is 0.8 A
and in the 6 and 4 ohm resistnace is 1.2A
(c)Potential across 6 ohm resistnace = 2*6 = 12 V (V=IR)
Across 15 ohm resistance = 15*0.8 = 12 V
Across 6 ohm in branch = 1.2*6 = 7.2 V
Across 4 ohm in branch = 1.2*4 = 4.8 V

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.