An inductor has a current I(t) = (0.420 A) cos[(265 s -1 ) t ] flowing through i

Question

An inductor has a current I(t) = (0.420 A) cos[(265 s-1)t] flowing through it. If the maximum emf across the inductor is equal to 0.430 V, what is the self-inductance of the inductor?

Part A An inductor has a current I(t) (0.420 A) cos(265 s inductor? flowing through it. If the maximum emf across the inductor is equal to 0.430 V, what is the self-inductance of the An inductor has a current I() = (0.420 A) cos[265 s-1M flowing through it. If the maximum emf across the inductor is equal to 0.430 V, what is the self-inductance of the 4.64 mH 3.09 mH O5.41 mH 2.32 mH 3.86 mH

Explanation / Answer

here,

peak voltage , V = 0.43 V

I(t) = (0.42) cos((265 s^-1)t)

dI/dt = d( (0.42) cos((265 s^-1)t)) /dt

dI/dt = (-0.42 * 265) sin( 265*t s^-1 )

let the inductnace be L

V = L * dI/dt

0.43 = L * ( 0.42 * 265)

L = 3.86 * 10^-3 H

L = 3.86 mH

the self inductnace is 3.86 mH

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