The angle through which a disk drive turns is given by ( t )= a + b t c t 3, whe

Question

The angle through which a disk drive turns is given by (t)=a+btct3, where a,b and care constants, t is in seconds, and is in radians. When t=0,=/4rad and the angular velocity is 2.50 rad/s , and when 1.10 s , the angular acceleration is 1.40 rad/s2 .

Part A

Find a including their units.

SubmitMy AnswersGive Up

Part B

Find b including their units.

SubmitMy AnswersGive Up

Part C

Find c including their units.

SubmitMy AnswersGive Up

Part D

What is the angular acceleration when =/4rad?

SubmitMy AnswersGive Up

Part E

What is when the angular acceleration is 4.40 rad/s2 ?

SubmitMy AnswersGive Up

Part F

What is the angular velocity when the angular acceleration is 4.40 rad/s2 ?

SubmitMy AnswersGive Up

The angle through which a disk drive turns is given by (t)=a+btct3, where a,b and care constants, t is in seconds, and is in radians. When t=0,=/4rad and the angular velocity is 2.50 rad/s , and when 1.10 s , the angular acceleration is 1.40 rad/s2 .

Part A

Find a including their units.

Find  including their units. /4rad/s2 /2rad/s /4rad /4rad/s

SubmitMy AnswersGive Up

Part B

Find b including their units.

Find  including their units. 2.50 rad/s2 2.50 rad/s 5.3 rad/s 5.3 rad/s2

SubmitMy AnswersGive Up

Part C

Find c including their units.

Find  including their units. -0.212 rad/s3 -0.212 rad/s2 3.3 rad/s3 4.5 rad/s3

SubmitMy AnswersGive Up

Part D

What is the angular acceleration when =/4rad?

=   rad/s2  

SubmitMy AnswersGive Up

Part E

What is when the angular acceleration is 4.40 rad/s2 ?

=   rad  

SubmitMy AnswersGive Up

Part F

What is the angular velocity when the angular acceleration is 4.40 rad/s2 ?

=   rad/s  

SubmitMy AnswersGive Up

Explanation / Answer

= a + bt ct^3

When t = 0, = a = /4 rad

(A) Hence, a = /4 rad

w = d/dt = b - 3ct^2

At t = 0, w = b = 2.5 rad/s

(B) Hence, b = 2.5 rad/s

alpha = dw/dt = - 6ct

At t = 1.1s, alpha = - 6 c * 1.1 = 1.4

(C) c = - 1.4/(1.1*6) = - 0.212 rad/s^2

(D) = - 6 c t = - 6 * - 0.212 * pi/4 = 1 rad/s^2

(E) Given = 4.4 rad/s^2

- 6 * - 0.212 * t = 4.4

t = 4.4/(6*0.212) = 3.46 s

   = a+btct3, = (pi/4) + 2.5*3.46 - (-0.212*3.46^3) = 18.21 rad

(F) w = b - 3 c t^2 = 2.5 - (3*-0.212*3.46^2) = 10.11 rad/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.