The angle thata through which a disk drive turns is given by theta(t)=a+bt-ct^3

Question

The angle thata
through which a disk drive turns is given by theta(t)=a+bt-ct^3 where a,b and c are constants.

t is in seconds, and theta is in radians. when t=0 sec , theta= bai/4 rad and the anguler velocity is 1.90 rad/sec and when 1.80 sec the anguler accelration is 1.20 rad/s^2

A find a incloding their unit?

B-Find b including their units.

C-Find c including their units.

D-What is the angular acceleration when theta =bai/4 rad

E-What is theta when angular acceleration is 4.00

rad/s^2 ?

F-What is the angular velocity when the angular acceleration is 4.00

rad/s^2s^2 ?

Explanation / Answer

a = pai/4 rad

b = 1.9 rad/sec

c = -0.11 rad/sec^3

Angular acceleration is zero when theta = pi/4

Theta when angular acc is 4 is 35.945 Radians

Angular velocity = 13.9 rad/s

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