long rod, insulated to prevent heat loss along its sides, is in perfect thermal

Question

long rod, insulated to prevent heat loss along its sides, is in perfect thermal contact with boiling water (at atmospheric pressure) at one end and with an ice-water mixture at the other (Figure 1) . The rod consists of a 1.00m section of copper (with one end in the boiling water) joined end-to-end to a length L2 of steel (with one end in the ice water). Both sections of the rod have cross-sectional areas of 4.00 cm2. The temperature of the copper-steel junction is 65.0C after a steady state has been reached. Assume that the thermal conductivities of copper and steel are given by kcopper=385WmK and ksteel=50.2WmK. Part A How much heat per second H (=Qt) flows from the boiling water to the ice-water mixture? Express your answer in watts.

Explanation / Answer

The heat traveling through the copper rod = K*A*dT/l = 385*0.0004*35/1 = 5.39 W.
Heat will travel through the steel at the same rate.

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