To understand the basic concepts of projectile motion. Projectile motion may see

Question

To understand the basic concepts of projectile motion.

Projectile motion may seem rather complex at first. However, by breaking it down into components, you will find that it is really little different from the one-dimensional motions that you may already have studied.

One of the most often used techniques in physics is to divide two- and three-dimensional quantities into components. For instance, in projectile motion, a particle has some initial velocity v . In general, this velocity can point in any direction in the xy plane and can have any magnitude. To make a problem more manageable, it is common to break up such a quantity into its x component v x and its y component v y.

Consider a particle with initial velocity v  that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

Part A

What is the x component v x of v ?

Express your answer in meters per second

Part B

What is the y component v y of v ?

Express your answer in meters per second.

Now, consider this applet. Two balls are simultaneously dropped from a height of 5.0 m.

Part D

How long tg does it take for the balls to reach the ground? Use 10 m/s2 for the magnitude of the acceleration due to gravity.

Express your answer in seconds to one significant figure.

Explanation / Answer

Here ,

initial velocity , v = 12 m/s

theta = 60 above negative x - axis

part A)

x - component of V , Vx = -12 * cos(60)

x - component of V , Vx = -6 m/s

part B)

y - component of V , Vy = V * sin(60)

y - component of V , Vy = 12 * sin(60)

y - component of V , Vy = 10.4 m/s

height , h = 5 m

part D)

time taken for ball to fall ,

tf = sqrt(2h/g)

tf = sqrt(2 *5/9.8)

tf = 1.01 s

the time taken for the ball to reach the ground is 1.01 s

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