A 4.30-kg box sits at rest at the bottom of a ramp that is 7.50 m long and that

Question

A 4.30-kg box sits at rest at the bottom of a ramp that is 7.50 m long and that is inclined at 40.0 ? above the horizontal. The coefficient of kinetic friction is ?k = 0.40, and the coefficient of static friction is ?s = 0.43.

Problem 5.70 Part A A 4.30-kg box sits at rest at the bottom of a ramp that is 7.50 m long and that is inclined at 40.0 above the horizontal. The coefficient of kinetic friction is = 0.40, and the coefficient of static friction is ,-0.43. What constant force F, applied parallel to the surface of the ramp, is required to push the box to the top of the ramp in a time of 3.60 s? Express your answer with the appropriate units. ? F Value Units Submit My Answers Give Up Provide Feedback Continue

Explanation / Answer

Apply kinematic equation to the block on the ramp

the accleration of the block

s = ut + 1/2 a t^2

= ot + 1/2 at^2

a = 2s/t^2 = 2 (7.5)/(3.6)^2 = 1.15 m/s^2

Fnet = F- mg sin theta - fk

ma = F- mg sin theta- uk mg cos theta

F = m( a+ g ( sin theta + uk cos theta)

= 4.30( 1.15+ 9.8 ( sin40+0.4 cos40)

=44.926 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.