A car(m = 1.50 times 10^2 kg) accelerates uniformly from rest to 18.0 m/s in 7.0

Question

A car(m = 1.50 times 10^2 kg) accelerates uniformly from rest to 18.0 m/s in 7.00 s. Assume that a single horizontal force acceleration the vehicle. determine the work done by this force on the car. determine the average power required to accelerate the car. A student, starting from rest, slides down a water sink. On the way down, a kinetic frictional force (a nonconservative force) acts on her. The student has a mass of 69 kg. and the height of the water slide is 11.0 m. If the kinetic frictional force does - 5.7 times 10^3 ] of work, how fast is the student going at the bottom of the slide

Explanation / Answer

From law of conservation of energy Pontential Energy = some of Kinetic Energy and Work Done

mgh = 1/2 mv2 +W

1/2 mv2 = mgh - W

1/2x69xv2 = 69x9.8x11 - 5.7x103

v2 = 1738.2/ 34.5= 50.38

Her velocity at the bottom of the slide is v= 7.1m/s

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