Please show full solutions. Thanks! Answers: a) 500 V/m b) -5 V c) 8.79 m/s Two

Question

Please show full solutions. Thanks!

Answers:

a) 500 V/m

b) -5 V

c) 8.79 m/s

Two very large flat, parallel plates are located 2 cm from each other. One plate is positively charged while the other is negatively charged. The potential difference between the two plates is 10 V. (a) Calculate the magnitude of the electric field at a point halfway between the two plates. (b) Calculate the electric potential halfway between the two plates. Assume the potential of the positive plate is 0. (c) An electron is placed halfway between the two places and released from rest. How fast is the electron moving 10^-13 seconds later.

Explanation / Answer

8) given

d = 2 cm = 0.02 m

V = 10 volts

a) E = V/d

= 10/0.02

= 500 V/m

b) let vp = 0

vm is the potentail at mid point.

vP - Vm = E*(d/2)

vP - vm = 500*(0.02/2)

vp - vm = 5

0 - vm = 5

==> vm = -5 volts

c) Apply, F = q*E

m*a = q*E

a = q*E/m

= 1.6*10^-19*500/(9.1*10^-31)

= 8.79*10^13 m/s^2

apply, v = u + a*t

= 0 + 8.79*10^13*10^-13

= 8.79 m/s

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