To determine the specific heat of an object, a student heats it to 100 C in boil

Question

To determine the specific heat of an object, a student heats it to 100 C in boiling water. She then places the 73.8 g object in a 158 g aluminum calorimeter containing 105 g of water. The aluminum and water are initially at a temperature of 19.4 , and are thermally insulated from their surroundings.

HERE IS A LIST OF SOME SPECIFIC HEATS OF SOME MATERIALS

Substances Specific heat, J/(kgK) Water 4186 Beryllium 1820 Aluminum 900 Glass 837 Silicon 703 Iron (steel) 448 Copper 387 Silver 234 Gold 129 Lead 128

If the final temperature is 23.2 , what is the specific heat of the object? Referring to the table, ALSO PLEASE identify the material in the object.

Explanation / Answer

The heat given up by the water and aluminum are:
specific heat of water is 4.186 kJ/kgC
specific heat of Aluminum is 900 J/kgC
E1 = 4186 J/kgC x 0.105 x 3.8 = 1670.214 J
E2 = 900 J/kgC x 0.158 x 3.8 = 540.36 J

this total of 2210.574 J is removed from the unknown in cooling from 100 to 23.2 C

Again,
2210.574 = X J/kgC x 0.0738 x (100 - 23.2)

=> X = 390.02 J/kgC
Means the material of the object is copper.

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