Two people carry a heavy electric motor by placing it on a light board 1.70 m lo

Question

Two people carry a heavy electric motor by placing it on a light board 1.70 m long. One person lifts at one end with a force of 350 N , and the other lifts the opposite end with a force of 650 N .

Part A:What is the weight of the motor?

Part B:Where along the board is its center of gravity located?

Part C:Suppose the board is not light but weighs 220 N , with its center of gravity at its center, and the two people each exert the same forces as before. What is the weight of the motor in this case?

Part D:Where is its center of gravity located?

Thank you in advnace!

Explanation / Answer

A) weight of motor = 350 + 650 = 1000 N

B) 350y = 650(1.7-y) => y = 1.105 m (from the man applying less force)

C) W = 1000 - 220 = 780 N

D) 220 x 0.85 + 780 x y' = 1000 x 1.105 => y' = 1.177 m (from the man applying less force)

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