Calculate the size of the quantum involved in the excitation of (a) an electroni

Question

Calculate the size of the quantum involved in the excitation of (a) an electronic oscillation of period 2.50 fs, (b) an N-H molecular vibration of period 2.21 fs, (c) a balance wheel (m= 2 Kg) of period 1.0 ms. Also calculate the force constants for each of these vibrations. Express the results in joules and kilojoules per mole. (1 fs = 10-15 s)

Calculate the size of the quantum involved in the excitation of (a) an electronic oscillation of period 2.50 fs, (b) an N-H molecular vibration of period 2.21 fs, (c) a balance wheel (m= 2 Kg) of period 1.0 ms. Also calculate the force constants for each of these vibrations. Express the results in joules and kilojoules per mole. (1 fs = 10-15 s)

Explanation / Answer

(a) E = h*f

where E is the energy of the quantum, h is plancks constant (6.63x10^-34) and f is the frequency.

frequency=1/T=4*10^14

For the first we have E = 6.63 x 10^-34 *4*10^14 = 2.652*10^(-19) J

(b) f = 1/T = 1/2.21*10^-15 = 4.53 x 10^14 Hz
So E = 3 x 10^-19 J

(c) period =T=1ms

frequency=1000 Hz

energy=6.63*10^(-31) J

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