A squirrel running across your roof drops an acorn that slides down the roof and

Question

A squirrel running across your roof drops an acorn that slides down the roof and onto your horizontal driveway. Our goal is to find out how far away from the house the acorn lands.

Define your y axis as vertical (with positive y pointing from the ground toward the roof of the house) and your x axis as horizontal (with positive x pointing roughly in the direction the squirrel is facing when it releases the acorn), with the origin at the base of the house next to the driveway.

Answer the following questions in terms of the known quantities for this problem: initial speed (vi), roof angle (theta), and roof height (h). You may also use generally known constants such as the gravitational constant (g).

What accelerations does the acorn experience in the x and y directions? (You should use "g" whenever appropriate in your answer).

1. Ax =

2. Ay =

Using kinematics relationships, determine the x and y components of the acorn's velocity as a function of time

1. Vx =

2. Vy =

Using kinematics relationships, determine the acorn's position(as a function of time) in the x and y directions.

1. X =

2. Y =

Now that you have fully described the motion of the the acorn (with equations), we can approach answering the initial question. We want to know how far the acorn is away from the house when it lands. If we look at the x position equation, we see that we need to know the time that the acorn lands in order to find its x position.

The parameter we know something about at the the time when the acorn lands (tland) is the acorn's y position. Specifically, y(tland) = 0 . Use this condition and the following values to find the time when the acorn lands.

How far from the house does the acorn land?

x(tland) =

Please see:

https://www.chegg.com/homework-help/questions-and-answers/squirrel-running-across-roof-drops-acorn-slides-roof-onto-horizontal-driveway-goal-find-fa-q12568311

the answers given here are wrong

Explanation / Answer

1) Ax=0 Ay= -g=-9,81 m/s

2) Vx=d/(t*sin())

Vy= -1/(t*cos()) *( (y-H) + (1/2)*g*t*t)

3) y= H-(1/2)gt^2

x= v1*sin()*t

4)y= H-(1/2)gt^2

0=H-(1/2)gt^2

Tland=(2H/g)^1/2

Tland=(2*4/9,81)^1/2

Tland= 0,9 s

X(land)= v1*sin()t= 5 m/s *sin(30) * 0,9 s = 2,25 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.