You hold a laser pointer just above the water\'s surface and shine it nearly par

Question

You hold a laser pointer just above the water's surface and shine it nearly parallel to the surface, but tilted slightly down so that the beam enters the water 5.0 m from you. How far from you does the beam strike the bottom of the pool? What is the exit angle theta from the glass prism in Figure P18.56? There is just one angle of incidence beta onto a prism for which the light inside an isosceles prism travels parallel to the base and emerges at that same angle beta, as shown in Figure P18.57. Find an expression for beta in terms of the prism's apex angle alpha and index of refraction n. A laboratory measurement finds that beta = 52.2 degree for a prism triangle. What is the prism's

Explanation / Answer

Refractive index of glass = 1.5
Angle of incidence = 45

Using Snel''s law
n1 * sin(45) = n2 * sin(r)
1.0 * sin(45) = 1.5 * sin(r)
r = 28.0

Now,
45 + (90-28) + x = 180
x = 73

Angle of otherincidence at the surface of the prism = 90 - 73 = 17

Using Snell's Law again for the second boundary,
1.5 * sin(17) = 1.0 * sin()
= 26.0o

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