O 4/30/2016 11:55 PM A 33.3/100 Gradebook Print Calculator Periodic Table Questi
ID: 1512623 • Letter: O
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O 4/30/2016 11:55 PM A 33.3/100 Gradebook Print Calculator Periodic Table Question 5 of 6 Map pling Consider the following fusion reaction. Identify the missing product of the reaction by replacing the question marks in the box below. Tip: If you need to clear your work and reset the Li question marks, click the icon that looks like two red arrows in the menu below the box, How much energy, in megaelectronvolts (MeV), is released in this reaction? Number AE MeV O Previous ® Give Up & View Solution Check Answer Next H Ext HintExplanation / Answer
12H + 36Li ---> 37Li + 11H
Total mass number A,
RHS=2+6=8
Total atomic number
RHS=1+3=4
So,
That unknown element have the mass number of 7 and atomic number of 3.
Hence, 37Li is the unknown element.
Sum of the masses in RHS of the reaction,
The exact mass of 12H = 2.01410 a.m.u.
3Li6 =6.015123 a.m.u.
Total = 8.029223 a.m.u.
LHS
The exact mass of 3Li7 isotope = 7.01601 a.m.u.
1H1 = 1.00738 a.m.u.
Total = 8.02384 a.m.u.
M = Sum of the masses of products – Sum of the masses of reactants
= 8.02384 - 8.029223
= - 0.005383 a.m.u.
As there is decrease of mass, hence energy is being released.
The value of Q will be therefore Positive i.e.
Q = +0.005383 a.m.u. X 931.5 MeV/a.m.u = +5.011573 MeV
Hence the above reaction is exoergic.
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