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A). A square shaped ( 4.5 mm by 4.5 mm) metal rod has resistance of 1.19 ohm. Th

ID: 1513071 • Letter: A

Question

A). A square shaped ( 4.5 mm by 4.5 mm) metal rod has resistance of 1.19 ohm. The resistivity of material is 0.5* 1.19 *10^-6 ohm-m. What is the length of the rod in meter?
B). Two circular metal plates, separared by a distance 8.85 mm forms 50 nF capacitance. The space between the plates are filled with Tefflon material with epsilon_r = 2.2. Calculate the area of each plate. A). A square shaped ( 4.5 mm by 4.5 mm) metal rod has resistance of 1.19 ohm. The resistivity of material is 0.5* 1.19 *10^-6 ohm-m. What is the length of the rod in meter?
B). Two circular metal plates, separared by a distance 8.85 mm forms 50 nF capacitance. The space between the plates are filled with Tefflon material with epsilon_r = 2.2. Calculate the area of each plate.
B). Two circular metal plates, separared by a distance 8.85 mm forms 50 nF capacitance. The space between the plates are filled with Tefflon material with epsilon_r = 2.2. Calculate the area of each plate.

Explanation / Answer

here,

A)

area of the rod , a = 4.5^2 * 10^-6 m

resistance , r = 1.19 ohm

resistivity , p = 0.5 * 1.19 * 10^-6 ohm m

let the length of rod be l

p*l/a = r

0.5 * 1.19* 10^-6 * l/( 4.5^2 * 10^-6) = 1.19

l = 40.5 m

length of rod is 40.5 m

B)

sepration between the plates , d = 8.85 * 10^-3 m

capacitance , C = 50 * 10^-9 F

k = 2.2

let the area of each plate be a

k * epsilon0 * a /d = C

2.2 * 8.85 * 10^-12 * a /( 8.85 * 10^-3) = 50 * 10^-9

a = 22.73 m^2

the area of each plate is 22.73 m^2

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