Calvin Cliffs Nuclear Power Plant, located on the Hobbes River, generates 1.00 G
ID: 1513166 • Letter: C
Question
Calvin Cliffs Nuclear Power Plant, located on the Hobbes River, generates 1.00 GW of power. In this plant, liquid sodium circulates between the reactor core and a heat exchanger located in the superheated steam that drives the turbine. Heat is absorbed by the liquid sodium in the core, and released by the liquid sodium (and into the superheated steam) in the heat exchanger. The temperature of the superheated steam is 450 K. Heat is released into the river, and the water in the river flows by at a temperature of 27°C.
(a) What is the highest efficiency that this plant can have?
(b) How much heat is released into the river every second?
GW
(c) How much heat must be released by the core to supply 1.00 GW of electrical power?
GW
(d) Assume that new environmental laws have been passed to preserve the unique wildlife of the river. Because of these laws, the plant is not allowed to heat the river by more than 0.60°C. What is the minimum flow rate that the water in the Hobbes River must have?
L/s
Explanation / Answer
T2 = Temperature of water in river = 27 c = 27 + 273 = 300 K
T1 = Temperature of steam = 450 k
a) efficeincy is given as
= 1 - (T2/T1 )
= 1 - (300/450)
= 0.3333
b)
effiecieny is given as ::
= Pout/Pin
Pout = 1 x 109 W
inserting the values
(0.3333) = (1 x 109 )/Pin
Pin = 3.00 x 109 watt
heat realesed = heat input - heat output
heat relased = 3.00 x 109- 1 x 109
heat released = 2.00 x 109 watt
C)
Pin = 3.00 x 109 watt
d)
change in temperature = delta T = 0.60 C = 0.60 K (since change remains same in c and K)
mass of water heated = m
c = specific heat of water = 4186 J/kgK
the heat required can be given as
Q = m c delta T
mass if given as , m = density x volume = V
so Q = rho V c delta T
dividing both side by ''t'
(Q/t) = rho(V/t) c delta T
inserting the values
(Q/t) = heat released = 2.00 x 109watt
2.00 x 109= (1000)(V/t) (4186) (0.6)
V/t = 796.31 m3/sec
V/t = 796.31 x 103 L/sec
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.