Calorimetry Are my calculations correct? How would I find #4: Specific heat of m

Question

Calorimetry
Are my calculations correct? How would I find #4: Specific heat of metal, equation 25.5 (J/g*oC)

Experiment 25 Report Sheet Calorimetry Lab Sec Name Kim Smart Date Desk No. Specific Heat of a Metal Unknown No. Trial 1 Trial 2 3.95 L 1.852. 1. Mass of metal (g) 2. Temperature of metal (boiling water (C) 4,03 o 030 3. Mass of calorimeter (g) 4. Mass of calorimeter+ water (g) 5. Mass of water (g 6. Temperature of water in calorimeter 7. Maximum temperature of metal and water from graph (oC) d l 8. Instructor's approval of graph Calculations for Specific Heat of a Metal 1. Temperature change of water, AT 58IOJ TID 3. Temperature change of metal, AT(e) 4. Specific heat of metal, equation 25.5 (U g. 5. Average specific heat of metal (l g C) Data Analysis, B Show calculations for Trial 1 using the correct number of significant figures D LIMI 45/06 ATCC) 3) AT 214.5 4) s Experiment 25 301 183

Explanation / Answer

Trial 1 :

heat loss by metal = heat gained by water

67.852 g * S * 74.5 oC = 6180 J

or, S = 6180 J / (67.852 g * 74.5 oC ) = 1.22 J/gm/oC

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67.85 gm * S * 70oC = 5810 J

or, S = 1.09 J/gm/oC

Average = 1.22+1.09/2 =1.16J/gm/oC

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