A block of mass m = 10.0 kg is attached to the end of an ideal spring. Due to th

Question

A block of mass m= 10.0 kg is attached to the end of an ideal spring. Due to the weight of the block, the block remains at rest when the spring is stretched a distance h= 7.00 cm from its equilibrium length. (Figure 1) The spring has an unknown spring constant k. Take the acceleration due to gravity to be g = 9.81 m/s2 .

Part A

What is the spring constant k?

Part B

Suppose that the block gets bumped and undergoes a small vertical displacement. Find the resulting angular frequency of the block's oscillations about its equilibrium position.

Express your answer in radians per second

Explanation / Answer

A)

spring constant k = mg/h = 20*9.81/0.07 = 2802.86 N/m

B)

angular frequency w = sqrt(k/m) = sqrt(2802.86/10) = 16.74 rad/s

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