A block of mass m 2.33 ko and a block of mass m2 6.50 kg are connected by a mass

Question

A block of mass m 2.33 ko and a block of mass m2 6.50 kg are connected by a massless string over a pulley in the shape of a solid disk having radius R angle ?-30.0°. The coefficient of kinetic friction is 0.360 for both blocks. Draw free-body diagrams of both blocks and of the pulley. 0.250 m and mass M-10.0 kg. These blocks are allowed to move on a fioxed M, R (a) Determine of the two blocks. The response you a u submitted has the wrong sign (b) Detarmine the tansions in the string on both sidas of the pulley. left of the pulley right of the pullay

Explanation / Answer

here,

m1 = 2.35 kg

m2 = 6.5 kg

R = 0.25 m

mass of pulley , M = 10 kg

theta = 30 degree

a)

the accelration , a = net force /effective mass

a = m2 * g * sin(theta)/(m1 + m2 + 0.5 * M * R^2 /R^2)

a = 6.5 * 9.81 * sin(30) /(2.35 + 6.5 + 0.5 * 10) m/s^2

a = 2.3 m/s^2

b)

let the tension in the left side and right side pulley be Tl and Tr

for m1

Tr = m1 * a = 2.35 * 2.3 N = 5.41 N

for m2

m2 * g * sin(theta) - Tr = m2 * a

Tr = 6.5 * ( 9.81 * sin(30) - 2.3) N

Tr = 16.9 N

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