A billiard ball moving at 5.60 m/s strikes a stationary ball of the same mass. A

Question

A billiard ball moving at 5.60 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 5.12 m/s at an angle of 24.0 degree with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision. magnitude_________m/s direction_________degree (with respect to the original line of motion) A 0.300 kg puck, initially at rest on a horizontal, frictionless surface, is struck by a 0.200 kg puck moving initially along the x axis with a speed of 2.00 m/s. After the collision, the 0.200 kg puck has a speed of 1.00 m/s at an angle of theta = 55.0 degree to the positive x axis (Fig. 8.11). Active Figure 8.11 (a) Determine the speed of the 0.300 kg puck after the collision._________m/s (b) Find the fraction of kinetic energy lost in the collision._________

Explanation / Answer

V2f = V1i - V1f = 5.60 - 5.12 [cos 24, sin 24]

= [0.920, 2.08] m/s

V2f = sqrt [0.9202 + 2.082] = 2.27 m/s

phi = tan-1 [2.08 / 0.920]

= 66.13 deg

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