The knight from a chess set is placed at the focal point of a diverging lens as
ID: 1518352 • Letter: T
Question
The knight from a chess set is placed at the focal point of a diverging lens as shown. By either carefully constructing a ray diagram or using the lens equation, determine where the image of the knight will appear?
A
no image is formed
B
the image is at a distance f to the left of the lens, but it is inverted
C
the image is at a distance f to the right of the lens, but it is upright
D
the image is at a distance f/2 to the right of the lens, but it is inverted
E
the image is at a distance f/2 to the left of the lens, but it is upright
A
no image is formed
B
the image is at a distance f to the left of the lens, but it is inverted
C
the image is at a distance f to the right of the lens, but it is upright
D
the image is at a distance f/2 to the right of the lens, but it is inverted
E
the image is at a distance f/2 to the left of the lens, but it is upright
Explanation / Answer
forcal alength= -f (negative because the lens is diverging)
distance of object= do= f
we need distance f image di
using lens formula
1/f= 1/do+ 1/di
1/-f = 1/f + 1/di
-1/f - 1/f = di
di= -f/2 so the image is formed at a distance of f/2 to the left(because di is negative) and is upright.so option d is correct.
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