An ideal air-filled parallel-plate capacitor has round plates and carries a fixe
ID: 1519883 • Letter: A
Question
An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its plates. All the geometric parameters of the capacitor (plate diameter and plate separation) are now DOUBLED. If the original energy stored in the capacitor was u_0, how much energy does it now store? U_0/2 U_0/4 4u_0 When two or more capacitors are connected in series across a potential difference each capacitor carries the same amount of charge. the potential difference across the combination is the algebraic sum of the potential differences across the individual capacitors. the equivalent capacitance of the combination is less than the capacitance of any of the capacitors. All of the above choices are correct. None of the above choices are correct. A 6.00-pF parallel-plate capacitor has charges of plusminus 40.0 mu C on its plates. How much potential energy is stored in this capacitor? 123 mu J 133 mu J 113 mu J Consider Fig. 2 on the screen. Each resistor is 4 Ohm. What is the current through R_B? 2/3A 7/3 A 5/3 A Consider Fig.2 on the screen. Each resistor is 4 Ohm. Assume the zero of potential is at the negative terminal of the 12-V battery, what is the potential at point, a? 3V 5.3 V 0V 14.7 V 6VExplanation / Answer
6) Uo = 0.5*C*V^2
when the parameters are doubled
A' = pi*(2*r)^2 = 4*pi*r^2 = 4*A
new capacitance is C' = eo*A'/d = 4*eo*A/d = 4*C
New energy is U = 0.5*C'*V^2 = 0.5*4*C*V^2 = 4*Uo
7) in series comination
charge Q is same across all capacitors
V = V1+V2+V3...
So A and B are correct
equivalent capacitamce is Ceq
then 1/Ceq = (1/C1) + (1/C2) + (1/C3)+ ...........
So the C) is also correct
So fionally the answer is D) all of the above choices are correct
8) Potential energy is U = Q^2/(2*C) = (40*10^-6)^2/(2*6*10^-6) = 133 uJ
So the correct answer is B) 133 uJ
9) need figure
10) need figure
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