14. 0/1 points | Previous AnswersCJ9 22.P.021. Ask Your Teacher My Notes A circu

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14.0/1 points |  Previous AnswersCJ9 22.P.021.

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My Notes

A circular coil (900 turns, radius = 0.13 m) is rotating in a uniform magnetic field. At t = 0 s, the normal to the coil is perpendicular to the magnetic field. Att = 0.010 s, the normal makes an angle of = 45° with the field because the coil has made one-eighth of a revolution. An average emf of magnitude 0.100 V is induced in the coil. Find the magnitude of the magnetic field at the location of the coil.

Explanation / Answer

here,

number of turns , n = 900

radius , r = 0.13 m

phi = 45 degree

time taken , t = 0.01 s

EMF induced , V = 0.1 V

let the magnetic feild be B

n * area *cos(phi) * B/t = V

900 * pi * 0.13^2 * cos(45) * B/0.01 = 0.1

B = 2.96 * 10^-5 T

the magnitude of the magnetic feild at the location is 2.96 * 10^-5 T

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