Two charges are placed on a line as shown below and as usual we define V=0 at pl

Question

Two charges are placed on a line as shown below and as usual we define V=0 at plusminus infinity If an object with charge of 2Q is placed on the line, at which position will its electrical potential energy be 0? x =-0.5 x = plusminus 0.5 x = -1 x = -7.5 x = 0 For the same charge configuration as in the previous problem, at which position will the object with charge 2Q experience 0 electrical force? x = -7.46 x =-6.00 x = -4.00 x = -0.54 Nowhere in the region shown. A 3 mu F capacitor is initially charged such that is has a potential difference of 10V between its plates. A second capacitor is connected by closing the switch S1. allowing charge to flow between the two. What is the energy stored in capacitor C_2? 50 mu J 3.8 mu J 5.0 mu J 28 mu J 3.0 mu J

Explanation / Answer

4.

let 2Q be placed in between the two charges

r = distance of 2Q from - 1Q

4 - r = distance of 2Q from 3Q

Electric potential energy is given as

k (2Q) (-Q)/r + k (2Q) (3Q)/(4 - r) = 0

r = 1 m

so 2Q is placed 1 m from -Q

so position = - 1 m

b)

let the charge be placed distance "r" from -Q towards left

net force on 2Q = 0

k (2Q) (Q) / r2 - k (2Q) (3Q) / (r + 4)2 = 0

r = 5.46 m

Position = - 2 - 5.46 = - 7.46

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