Two charges are placed on the x axis. One charge( q 1 = +14.5 µC) is at x 1 = +3

Question

Two charges are placed on the x axis. One charge(q1 = +14.5 µC) is at x1 = +3.0 cmand the other (q2 = -13 µC) is at x2 = +9.0 cm.Find the net electric field (magnitude and direction) at thefollowing locations. (a) x = 0 cm magnitude 1 N/C direction 2---Select----x direction+x direction
(b) x = +6.0 cm magnitude 3 N/C direction 4---Select----x direction+x direction (a) x = 0 cm magnitude 1 N/C direction 2---Select----x direction+x direction
(b) x = +6.0 cm magnitude 3 N/C direction 4---Select----x direction+x direction magnitude 1 N/C direction 2---Select----x direction+x direction

Explanation / Answer

(a) x = 0 cm magnitude 1 N/C direction 2---Select----x direction+x direction
(b) x = +6.0 cm magnitude 3 N/C direction 4---Select----x direction+x direction at x=0 electric field=9*109*10-6[14.5*/3*10-2-13/9*10-2]=21.501*105N/C direction   -x at x=4cm electric field=9*109*10-6[14.5*/3*10-2+13/3*10-2]=82.494*105N/C direction   +x electric field=9*109*10-6[14.5*/3*10-2+13/3*10-2]=82.494*105N/C direction   +x magnitude 1 N/C direction 2---Select----x direction+x direction

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