A Ping-Pong ball is acted upon by the Earth, air resistance, and a strong wind.
ID: 1522917 • Letter: A
Question
A Ping-Pong ball is acted upon by the Earth, air resistance, and a strong wind. Here are the positions of the ball at several times.
Early time interval:
At t = 13.06 s, the position was <5.58, 2.19, 9.07>m.
At t = 13.10 s, the position was <5.64, 2.07, 9.87> m.
Late time interval:
At t = 15.06 s, the position was <9.93, 7.59, 49.87>m.
At t = 15.10 s, the position was <10.04, 7.93, 50.67>m.
(a) In the early time interval, from t = 13.06 s to t = 13.10 s, what was the average momentum of the ball? The mass of the Ping-Pong ball is 2.7 grams (2.7 103 kg).
Express your result as a vector.
(b) In the late time interval, from t = 15.06 s to t = 15.10 s, what was the average momentum of the ball? Express your result as a vector.
(c) In the time interval from t = 13.06 s (the start of the early time interval) to t = 15.06 s (the start of the late time interval), what was the average net force acting on the ball? Express your result as a vector.
Explanation / Answer
Interval 1:
Change in position: <0.06, -0.12, -0.80> m
Change in time: 0.04 s
Average velocity: <1.5, -3, -0.20> m/s
mass: 2.7e-3 kg
Average momentum: <4.05e-3, -8.1e-3, -54e-3> kg*m/s
Interval 2:
Change in position: <0.11, 0.34, -0.8> m
Change in time: 0.04 s
Average velocity: <2.75, 8.5, -20> m/s
mass: 2.7e-3 kg
Average momentum: <7.425e-3, 22.95e-3, -54e-3> kg*m/s
Interval 3:
Change in momentum: <3.375e-3, 31.05e-3, 0>
Change in time: 2 s
Average Force: <1.6875e-3, 15.525e-3, 0> N
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