8. Suppose that the \"fabulous\" phenotype is controlled by two genes, A and B,

Question

8. Suppose that the "fabulous" phenotype is controlled by two genes, A and B, as shown in the diagram below. Allele A produces enough enzyme 1 to convert "plain" to "smashing." Allele a produces no enzyme1. Allele B produces enough enzyme 2 to convert "smashing" to "fabulous." Allele b produces no enzyme 2. The A and B genes are both autosomal and sort independently. Enzyme 1 Enzyme2 Plain Smashing Fabulous If a true-breeding "fabulous" male and a true-breeding "plain" female were to have offspring (F) who then mated with individuals of identical genotype to their own, what would be the expected ratio of the F, offspring? 9. Which of the following is UNLIKELY to be seen in a pedigree for an autosomal recessive trait? 10. Which of the following is UNLIKELY to be seen in a pedigree for an X-linked recessive trai?

Explanation / Answer

9.The possible pairs are AABB,AaBB,AABb,AaBb.since there is atleast one dominant allele from each gene producing possible gene pairs.Whereas in autosomal recessive trait, atleast two recessive allele must be present in any of the two non-allelic pair of genes.Therefore, fabulous phenotype could be UNLIKELY to be seen in a pedigree for an autosomal recessive trait.

10.Since A and B genes are both autosomal and are not present on the X-chromosome therefore, fabulous,Smashing and Plain is UNLIKELY to be seen in a pedigree for an X-linked recessive trait.

Related Questions

Navigate

• Browse (All)
• Browse 8
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.