Given information is: x,y axis first graph : a(m/s^2) is the Y and t(s) is the x

Question

Given information is: x,y axis

first graph : a(m/s^2) is the Y and t(s) is the x axis

second graph: v(m/s) is Y axis and t(s) is X axis

third graph: X(m) is Y axis and t(s) is X axis

tion Consider a one-dimensional acceleration that starts at zero at time zero, then increases to some maximum value, then decreases back to zero. Human pushing forces often create accelerations that fit this description; the pushing force is small when the hands of the human first make contact (assuming the fingertips touch first), large when the palms are flat against the object being pushed, and then small again as the fingertips are breaking contact with the object. This problem will ask you to find the resulting velocity and position equations for a particle subject to such an acceleration. vin (r) (m)

Explanation / Answer

Equation of velocity = dx/dt and e know that v=dx/dt

eq of acceleration is = dv/dt & d2x/dt2 because the acceleration is erivative of velocity and double derivativ of displacement

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