ers X saplinglearning.com/ibi 3300713 Print I calculator Periodic Table Sapling

Question

ers X saplinglearning.com/ibi 3300713 Print I calculator Periodic Table Sapling Learning Two skydivers are holding on to each other while faling straight down at a common terminal speed of 60.70 m/s. Suddenly, they push from each other. Immediately after separation, the first skydiver (who has a mass of 8380 the following (with "straight down" comesponding to the positive zaxis) 4.430 m/s 4.250 m/s 60.70 m/s the and of the velocity of the second skydiver, whose mass is 57.7o kg. after separation? immediately m/s What is the change in kinetic energy of the system? Joules taree s pertners privacy polcy teems or use contact

Explanation / Answer

vt = 60.7 m/s ; m1 = 83.8 kg ; m2 = 57.7 kg

v1x = 4.43 m/s ; v1y = 4.25 m/s ; v1z = 60.7 m/s

From the conservation of momentum:

In X direction:

(83.8 + 57.7) x 0 = 83.8 x 4.43 + 57.7 x v2x

v2x = -6.43 m/s

In Y direction:

(83.8 + 57.7) x 0 = 83.8 x 4.25 + 57.7 x v2y

v2y = -6.17 m/s

b)The change in KE would be calculated as follows:

Intial KE = 0.5 x (83.8 + 57.7) 60.7^2 = 260677.67 J

Final KE1 = 0.5 x 83.8 x [ 4.43^2 + 4.25^2 + 60.7^2] = 155959.342 J

Final KE2 = 0.5 x 57.7 x [-6.43^2 + 6.17^2 + 60.7^2] = 106202.62 J

total final kE = 155959.34 + 106202.62 = 262161.96

KE increases by :

delta KE = final - initial = 1484.29 J

Hence, delta KE = 1484.29 J

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