A rocket, initially at rest on the ground, accelerates straight upward from rest

Question

A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 39.2 m/s2 . The acceleration period lasts for time 6.00 s until the fuel is exhausted. After that, the rocket is in free fall. Part A Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 39.2 m/s2 . The acceleration period lasts for time 6.00 s until the fuel is exhausted. After that, the rocket is in free fall. Part A Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 39.2 m/s2 . The acceleration period lasts for time 6.00 s until the fuel is exhausted. After that, the rocket is in free fall. Part A Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80

Explanation / Answer

here,

for accelration , a = 39.2 m/s^2

and t = 6 s

the height achived , h1 = u0 * t + 0.5 * a * t^2

h1 = 0 + 0.5 * 39.2 * 6^2

h1 = 352.8 m

final speed , v = u0 + a * t

v = 0 + 39.2 * 6 = 235.2 m/s

when under free fall

the height achived , h2 = v^2 /2g

h2 = 2822.4 m

the maximum height reached is (h1 + h2 = 3175.2 m)

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