A small metal bead, labeled A, has a charge of 25 nC . It is touched to metal be

Question

A small metal bead, labeled A, has a charge of 25 nC . It is touched to metal bead B, initially neutral, so that the two beads share the 25 nC charge, but not necessarily equally. When the two beads are then placed 5.0 cm apart, the force between them is 4.8×104 N . Assume that A has a greater charge.

A small metal bead, labeled A, has a charge of 25 nC . It is touched to metal bead B, initially neutral, so that the two beads share the 25 nC charge, but not necessarily equally. When the two beads are then placed 5.0 cm apart, the force between them is 4.8×104 N . Assume that A has a greater charge.

Explanation / Answer

here,

qa + qb = 25*10^-9 C
qa = (25*10^-9 - qb)

distance b/w the charges, d = 5 cm = 0.05 m

electrostatic force, F = 4.8*10^-4 N

From columb's law , electric force is :
F = k*qa*qb/r^2
F = K*(25*10^-9 - qb)/r^2
(4.8*10^-4) = 9*10^9 * (25*10^-9 - qb)*qb/(0.05)^2
qb = 7.713*10^-9 C

therefore
qa = ((25*10^-9) - (7.713*10^-9))

qa = 17.287*10^-9 C

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